\(\%S\left(FeS\right)=\dfrac{32}{32+56}.100\%=36,36\%\\ \%S\left(FeS_2\right)=\dfrac{32.2}{56+32.2}.100\%=53,33\%\\ \%S\left(H_2SO_4\right)=\dfrac{32}{98}.100\%=32,65\%\\ \%S\left(H_2S\right)=\dfrac{32}{32+2}.100\%=94,11\%\\ \%S\left(SO_2\right)=\dfrac{32}{64}.100\%=50\%\)