\(P=1+\frac{1}{2}.\frac{\left(1+2\right).2}{2}+\frac{1}{3}.\frac{\left(3+1\right).3}{2}+...+\frac{1}{2012}.\frac{\left(2012+1\right).2012}{2}\)
\(=1+\frac{\left(1+2\right)}{2}+\frac{\left(1+3\right)}{2}+...+\frac{\left(1+2012\right)}{2}\)
\(=1+\frac{2011}{2}+\frac{\left(2012+2\right).2011}{2}=1+\frac{2011}{2}+2011.1007\)