Question

Tính nhanh:

\(\left(2012\cdot2010+2010\cdot2008\right)\cdot\left(1+\frac{1}{2}:1\frac{1}{2}-1\frac{1}{3}\right)\)

Answer 1

(2012.2010+2010.2008).\(\left(1+\frac{1}{2}:1\frac{1}{3}-1\frac{1}{3}\right)\)= (2012.2010+2010.2008).(\(\left(1+\frac{1}{2}:\frac{3}{2}-\frac{4}{3}\right)\)

                                                                                      =(2012.2010+2010.2008).0=0

Đây là mình làm tắt bạn có thể giải chi tiết hơn....Chúc bạn học tốt

Answer 2

\(\left(2012\times2010+2010\times2008\right)\times\left(1+\frac{1}{2}:1\frac{1}{2}-1\frac{1}{3}\right)\)

\(=\left(2012\times2010+2010\times2008\right)\times\left(1+\frac{1}{2}:\frac{3}{2}-1\frac{1}{3}\right)\)

\(=\left(2012\times2010+2010\times2008\right)\times\left(1+\frac{1}{3}-1\frac{1}{3}\right)\)

\(=\left(2012\times2010+2010\times2008\right)\times0=0\)

Answer 3

\(\left(2012.2010+2010.2008\right)\left(1+\frac{1}{2}:1\frac{1}{2}-1\frac{1}{3}\right)\)

= \(2010\left(2012+2008\right)\left(1+\frac{1}{3}-\frac{4}{3}\right)\)

\(=2010.4020.0\)

= 0

Answer 4

Ta có:\(\left(2012.2010+2010.2008\right).\left(1+\frac{1}{2}:1\frac{1}{2}-1\frac{1}{3}\right)=\left(2012.2010+2010.2008\right).\left(1+\frac{1}{3}-1\frac{1}{3}\right)\)

\(=\left(2012.2010+2010.2008\right).0=0\)

Answer 5

\(\left(2012.2010+2010.2008\right).\left(1+\frac{1}{2}:1\frac{1}{2}-1\frac{1}{3}\right)\)

\(=\left(2012.2010+2010.2008\right).\left(1+\frac{1}{2}:\frac{3}{2}-\frac{4}{3}\right)\)

\(=\left(2012.2010+2010.2008\right).\left(1+\frac{1}{2}.\frac{2}{3}-\frac{4}{3}\right)\)

\(=\left(2012.2010+2010.2008\right).\left(1+\frac{1}{3}-\frac{4}{3}\right)\)

\(=\left(2012.2010+2010.2008\right).\left(1+\frac{1}{3}-\frac{4}{3}\right)\)