Question

Tính nhanh:

\(\left(1+\frac{1}{100}\right)\cdot\left(1+\frac{1}{99}\right)\cdot\left(1+\frac{1}{98}\right)\cdot...\cdot\left(1+\frac{1}{2}\right)\)

. là nhân nhé còn ... là vâng vâng

Answer 1

\(\left(1+\frac{1}{100}\right).\left(1+\frac{1}{99}\right)............\left(1+\frac{1}{2}\right)\)

\(=\frac{101}{100}.\frac{100}{99}..............\frac{3}{2}\)

\(=\frac{101.100............3}{100.99...............2}\)

\(=\frac{101}{2}\)

Answer 2

\(=\frac{101}{100}.\frac{100}{989}.....\frac{3}{2}=\frac{101}{2}\)

Answer 3

\(\left(1+\frac{1}{100}\right).\left(1+\frac{1}{99}\right).\left(1+\frac{1}{98}\right)...\left(1+\frac{1}{2}\right)\)

\(=\frac{101}{100}.\frac{100}{99}.\frac{99}{98}...\frac{3}{2}\)

\(=\frac{101}{2}\)

Ủng hộ mk nha ^_^

Answer 4

101/100.100/99.99/98.98/97.........3/2

Rút gọn mẫu cho mẫu,tử cho tử,ta còn:

101/2

Chúc em học tốt