\(\frac{60\times48+120\times31}{55\times16+55\times4}=\frac{60\times2\times24+120\times31}{55\times\left(16+4\right)}\)
\(=\frac{120\times24+120\times31}{55\times20}\)
\(=\frac{120\times\left(24+31\right)}{55\times20}\)
\(=\frac{120\times55}{55\times20}=6\)
\(\frac{60\times48+120\times31}{55\times16+55\times4}=\frac{60\times48+60\times62}{110\times8+110\times2}=\frac{60\times\left(48+62\right)}{110\times\left(8+2\right)}=\frac{60\times110}{110\times10}=\frac{60}{10}=6\)