\(\left(\frac{1999}{2011}-\frac{2001}{1999}\right)-\left(\frac{-12}{1999}-\frac{12}{2001}\right)=\frac{1999}{2011}-\frac{2011}{1999}+\frac{12}{1999}+\frac{12}{2001}\)
\(=\left(\frac{1999}{2011}+\frac{12}{2011}\right)+\left(\frac{-2011}{1999}+\frac{12}{1999}\right)=\frac{2011}{2011}+\left(\frac{-2011}{2011}\right)=1+\left(-1\right)=0\)
Tính Nhanh:\(\frac{1999}{2011}-\frac{2011}{1999}-\left(\frac{-12}{1999}-\frac{12}{2011}\right)\)
Tính nhanh:
\(\left(\frac{1999}{2011}-\frac{2011}{1999}\right)-\left(\frac{-12}{1999}-\frac{12}{2011}\right)\)
Tính nhanh: \(\left(\frac{1999}{2011}-\frac{2011}{1999}\right)-\left(\frac{-12}{1999}-\frac{12}{2011}\right)\)
tính nhanh
\(\left(\frac{1999}{2011}-\frac{2011}{1999}\right)\)-\(\left(\frac{-12}{1999}-\frac{12}{2011}\right)\)
tính nhanh
\(\left(\frac{1999}{2011}-\frac{2011}{1999}\right)-\left(\frac{-12}{1999}-\frac{12}{2011}\right)\)
\((\frac{1999}{2011} - \frac{2011}{1999}) - (\frac{-12}{1999} - \frac{12}{2011}) \)
\(\frac{-2011}{2012}:\left\{\frac{1999}{2011}-\frac{2011}{2012}\right\}+\frac{1999}{2011}:\left\{\frac{1999}{2011}-\frac{2011}{2012}\right\}=?\)
Ai đó giúp mình giải nha, cảm ơn
Mọi người giải giúp mình nha, xin cảm ơn
\(\frac{-2011}{2012}:\left\{\frac{1999}{2011}-\frac{2011}{2012}\right\}+\frac{1999}{2011}:\left\{\frac{1999}{2011}-\frac{2011}{2012}\right\}\)
\(\frac{-2011}{2012}\): (\(\frac{1999}{2011}\)-\(\frac{2011}{2012}\)) + \(\frac{1999}{2011}\):(\(\frac{-2011}{2012}\)+\(\frac{1999}{2011}\))
