\(\frac{11\cdot3^{32}\cdot3^8-9^{15}\cdot3}{\left(2\cdot3^{15}\right)^2}\)
\(=\frac{11\cdot3^{40}-3^{30}\cdot3}{2^2\cdot3^{30}}\)
\(=\frac{11\cdot3^{40}-3^{31}}{2^2\cdot3^{30}}\)
\(=\frac{3^{31}\cdot\left(11\cdot3^{19}-1\right)}{2^2\cdot3^{30}}\)
\(=\frac{3\cdot\left(11\cdot3^{19}-1\right)}{2^2}\)
ai tính nhanh được tiếp thì giải ra mik xem vs