Question

tính nhanh:

A,\(\frac{254x399-145}{254+399\text{x}253}\)B,\(\frac{5932+6001\text{x}5931}{5931\text{x}6001-69}\)

ai xong cho 3 tích và đúng, chữ x là dấu nhân nhé!

Answer 1

#)Giải :

A, \(\frac{254x399-145}{254+399x253}\)

\(=\frac{253x399+399-145}{254+399x253}\)

\(=\frac{253x399+254}{254+399x253}\)

\(=1\)

B, \(\frac{5932+6001x5931}{5931x6001-69}\)

\(=\frac{5932+6001x5931}{\left(5931+1\right)x6001-69}\)

\(=\frac{5932+6001x5931}{5931x6001+6001-69}\)

\(=\frac{5932+6001x5932}{5932x6001+5932}\)

\(=1\)

         #~Will~be~Pens~#

Answer 2

\(\frac{254x399-145}{254+399x253}=\frac{\left(253+1\right)x399-145}{254+399x253}=\frac{253x399+1x399-145}{254+399x253}=\frac{253x399+254}{254+399x253}\)

\(=1\)

Answer 3

\(\frac{254x399-145}{254+399x253}\)

=\(\frac{\left(253+1\right)x399-145}{254+399x253}\)

=\(\frac{253x399+399-145}{254+399x253}\)

=\(\frac{253.399+254}{254+399x253}\)=\(1\)

\(\frac{5932+6001x5931}{5931x6001-69}\)

=\(\frac{5932+6001x5931}{\left(5931+1\right)x6001-69}\)

=\(\frac{5932+6001x5931}{5931x6001+6001-69}\)

=\(\frac{5932+6001x5931}{5931x6001x5932}\)=1

# Hok tốt