a) \(\frac{930}{15}\)- \(\frac{310}{15}\)- 196= \(\frac{620}{15}\)- 196= \(-\frac{464}{3}\).
b) \(\frac{572}{26}\)- \(\frac{156}{13}\)= 22- 12= 10.
\(\frac{930}{15}\)- \(\frac{310}{15}\)- \(196\)=\(\frac{712}{3}\)
\(\frac{572}{26}\)- \(\frac{156}{13}\)=\(\frac{572}{26}-\frac{312}{26}\)=\(\frac{260}{20}=10\)