Question

Tính nhanh:(1²+2²+3²+...+1 000 000²).(91-273:3)

Giúp tớ :)))

Answer 1

\(\left(1^2+2^2+3^2+...+1000000^2\right).\left(91-273:3\right)\\ =\left(1^2+2^2+3^2+...+1000000^2\right).0=0\)

Answer 2

(1²+2²+3²+..+1000000²).(91-273:3)
=(1²+2²+3²+..+1000000²).(91-91)

=(1²+2²+3²+..+1000000²).0

=0

Answer 3

[1²+ 2²+3²+...+1000 000²].[91 - 273:3]

[1²+2²+3²+....+1000 000²].0 

=0