Question

 Tính nhanh:

Answer 1

\(A=\dfrac{2004.37+2004+2.2004+2004.59+2004}{324.321-201.324-324.101-18.324}\)
\(=\dfrac{2004.\left(37+1+2+59+1\right)}{324.\left(321-201-101-18\right)}=\dfrac{2004.100}{324.1}=\dfrac{200400}{324}=\dfrac{16700}{27}\)

Answer 2

\(\dfrac{2004.37+2004+2.2004+2004.59+2004}{324.321-201.324-101.324-18.324}\)

=\(\dfrac{2004.\left(37+1+2+59+1\right)}{324.+\left(321-201-101-18\right)}\)

=\(\dfrac{2004.100}{324.1}\).

=\(\dfrac{200400}{324}\)

=\(\dfrac{16700}{27}\)