\(\frac{4}{9}\).\(\frac{13}{3}\)-\(\frac{4}{3}\).\(\frac{40}{9}\)
=\(\frac{4}{9}\).\(\frac{13}{3}\)-\(\frac{4}{9}\).\(\frac{40}{3}\)
=\(\frac{4}{9}\).(\(\frac{13}{3}\)-\(\frac{40}{3}\))
=\(\frac{4}{9}\).(-9)
=\(\frac{-36}{9}\)
=-4
\(\frac{4}{9}\).\(\frac{13}{3}\)-\(\frac{4}{3}\).\(\frac{40}{9}\)
=\(\frac{4}{9}\).\(\frac{13}{3}\)-\(\frac{4}{9}\).\(\frac{40}{3}\)
=\(\frac{4}{9}\).(\(\frac{13}{3}\)-\(\frac{40}{3}\))
=\(\frac{4}{9}\).(-9)
=\(\frac{-36}{9}\)
=-4
tính nhanh
B=\(\frac{4}{9}.\frac{13}{3}-\frac{4}{3}.\frac{40}{9}\)
A=\(\frac{6}{7}+\frac{1}{7}.\frac{2}{7}+\frac{1}{7}.\frac{5}{7}\)
\(\frac{40}{9}\cdot\frac{4}{3}-\frac{4}{9}:\frac{13}{3}=....\)
Tính nhanh :
A=\(21\frac{4}{11}-\left(1\frac{3}{5}+7\frac{4}{11}\right)\)
B=\(\left(7\frac{8}{9}+2\frac{3}{13}\right)-\left(4\frac{8}{9}-7\frac{10}{13}\right)\)
C= \(\frac{-3}{5}+\frac{2}{7}+\frac{-3}{7}\cdot\frac{3}{5}+\frac{-3}{7}\)
TÍNH
\(B=\frac{3+\frac{8}{12}+\frac{9}{13}-\frac{12}{17}}{4+\frac{8}{12}+\frac{12}{13}-\frac{16}{17}}+\frac{4+\frac{16}{60}-\frac{24}{213}-\frac{32}{11}}{5+\frac{20}{61}-\frac{36}{213}-\frac{40}{11}}\)
Bài 1: tính nhanh
a)\(\frac{5}{7}.\frac{-7}{9}-\frac{5}{7}.\frac{2}{9}-\frac{5}{9}\)
b)\(\left(3\frac{1}{13}+2\frac{1}{4}\right)-2\frac{2}{13}\)
c)\(\frac{3}{15}.\frac{3}{7}-\frac{1}{5}.\frac{4}{-7}+\frac{4}{5}\)
giúp mình nha!
Câu hỏi: thực hiện phép tính
D= \(\frac{24.47-23}{24+47.23}\). \(\frac{3+\frac{3}{7}-\frac{3}{11}+\frac{3}{1001}-\frac{3}{13}}{\frac{9}{1001}-\frac{9}{13}+\frac{9}{11}+9}\)
E= \(\frac{\frac{1}{9}-\frac{1}{7}-\frac{1}{11}}{\frac{4}{9}-\frac{4}{7}-\frac{4}{11}}\). \(\frac{0,6-\frac{3}{25}-\frac{3}{125}-\frac{3}{625}}{\frac{4}{5}-0,16-\frac{4}{125}-\frac{4}{625}}\)
Dấu chấm là nhân, mong mọi người giải hộ
Tính nhanh:
a,\(15\frac{3}{13}\)- (\(3\frac{4}{7}\)+\(8\frac{3}{13}\))
b,(\(7\frac{4}{9}\)+\(4\frac{7}{11}\)) -\(3\frac{4}{9}\)
c,\(\frac{-7}{9}\). \(\frac{4}{11}\)+ \(\frac{-7}{9}\). \(\frac{7}{11}\)+
25% của A với A= \(\frac{4}{3}.\frac{13}{9}-\frac{4}{3}.\frac{40}{9}\)
trl hộ mk nha cảm ơn
Tính nha
\(\frac{-10}{13}+\frac{8}{17}-\frac{3}{13}+\frac{12}{17}-\frac{11}{20}\)
\(\frac{3}{4}+\frac{-5}{6}-\frac{11}{-12}\)
\(\left[13.\frac{4}{9}+2.\frac{1}{9}\right]-3.\frac{4}{9}\)