Question

Tính nhanh biểu thức sau:

\(A=\left(7-\frac{3}{4}+\frac{1}{3}\right)-\left(6+\frac{5}{4}-\frac{4}{3}\right)-\left(5-\frac{7}{4}+\frac{5}{3}\right)\)

Answer 1

\(A=7-\frac{3}{4}+\frac{1}{3}-6-\frac{5}{4}+\frac{4}{3}-5+\frac{7}{4}-\frac{5}{3}\)

\(A=7-6-5+\left(\frac{-3}{4}-\frac{5}{4}+\frac{7}{4}\right)+\left(\frac{1}{3}+\frac{4}{3}-\frac{5}{3}\right)\)

\(A=-4-\frac{1}{4}\)

\(A=\frac{-17}{4}\)

Answer 2

#)Giải :

\(A=\left(7-\frac{3}{4}+\frac{1}{3}\right)-\left(6+\frac{5}{4}-\frac{4}{3}\right)-\left(5-\frac{7}{4}+\frac{5}{3}\right)\)

\(A=7-\frac{3}{4}+\frac{1}{3}-6-\frac{5}{4}+\frac{4}{3}-5-\frac{7}{4}+\frac{5}{3}\)

\(A=\left(7-6-5\right)-\left(-\frac{3}{4}-\frac{5}{4}+\frac{7}{4}\right)+\left(\frac{1}{3}+\frac{4}{3}-\frac{5}{3}\right)\)

\(A=-4-\frac{1}{4}+0\)

\(A=-4\frac{1}{4}=-\frac{17}{4}\)

          #~Will~be~Pens~#