\(A=\frac{17}{19}x\frac{1}{6}+\frac{17}{19}x\frac{5}{6}\)
\(=\frac{17}{19}x\left(\frac{1}{6}+\frac{5}{6}\right)=\frac{17}{19}x1=\frac{17}{19}\)
A= \(\frac{1717}{1919}\text{ *}\frac{303}{1818}+\frac{17}{19}\text{ *}\frac{1515}{1818}\)
A= \(\frac{17}{19}\text{ *}\frac{3}{18}+\frac{17}{19}\text{ *}\frac{15}{18}\)
A= \(\frac{17}{19}\text{ *}\left(\frac{3}{18}+\frac{15}{18}\right)\)
A= \(\frac{17}{19}\text{ *}1\)
A= \(\frac{17}{19}\)
Vậy A= \(\frac{17}{19}\)
vVv Học tốt nhé bạn, mình sẽ rất vui nếu bạn k đúng cho mình, cảm ơn ban nhiều vVv
\(\frac{1717}{1919}x\frac{303}{1818}+\frac{17}{19}x\frac{1515}{1818}\)
= \(\frac{17}{19}x\frac{1}{6}\)+ \(\frac{17}{19}x\frac{5}{6}\)
= \(\frac{17}{19}\)x ( \(\frac{1}{6}+\frac{5}{6}\))
= \(\frac{17}{19}x1\)
= \(\frac{17}{19}\)