A = 22009 - 22008 - 22007 - ... - 22 - 2 - 1
A = 22009 - (22008 + 22007 + ... + 22 + 2 + 1)
Đặt B = 22008 + 22007 + ... + 22 + 2 + 1
2B = 22009 + 22008 + ... + 23 + 22 + 2
2B - B = (22009 + 22008 + ... + 23 + 22 + 2) - (22008 + 22007 + ... + 22 + 2 + 1)
B = 22009 - 1
=> A = 22009 - (22009 - 1) = 22009 - 22009 + 1 = 0 + 1 = 1
tinh nhanh
A=2^2009-2^2008-2^2007-.....-2^2-2^1-1
Tính nhanh :a)2/5+4/5 nhân 5/2
b)2008/2009-2009/2008+1/2009+2007/2008
tinh nhanh
a) 36*17-8.7*25+64*17-0.87*650
b) 2009*14+1994+2007*2008/2008+2008*505+504*2008
c) 1*1+2*2+3*3+4*4+5*5+...+98*98
TÍNH NHANH :
A= 2^2009 - 2^2008-2^2007 -....-2^2 - 2^1 - 1
Tính A= 2009/2+2008/(2^2)+2007/(2^3)+...+3/(2^2007)+2/(2^2008)+1/(2^2009)
Tính nhanh A=22009-22008-22007-......-22-21-1
2. So sánh A và B:
A= 2006/2007 - 2007/2008 + 2008/2009 - 2009/2010
B=-1/2006*2007 - 1/2008*2009
tinh A=1-2+3+4-5-6+7+8-9-...+2007+2008-2009-2010
a, Tính nhanh :
\(\frac{2009\times(1+\frac{1}{2}+\frac{1}{3}+...+\frac{1}{2007}+\frac{1}{2008})}{2008-\left(\frac{1}{2}+\frac{2}{3}+\frac{3}{4}+...+\frac{2006}{2007}+\frac{2007}{2008}\right)}\)
b, Cho \(\text{Q}=2+2^2+2^3+...+2^{10}\). Chứng tỏ rằng \(Q⋮3\).
