Question

Tính nhanh A= 2012 x 14 + 1997 + 2010 x 2011 / 2011 x5 + 2011 x 1008 + 1012 X 2011

Answer 1

Ta có : 

\(A=\frac{2012.14+1997+2010.2011}{2011.5+2011.1008+1012.2011}\)

\(\Rightarrow A=\frac{\left(2011+1\right).14+1997+2010.2011}{2011.\left(5+1008+1012\right)}\)

\(\Rightarrow A=\frac{2011.14+14+1997+2010.2011}{2011.2025}\)

\(\Rightarrow A=\frac{2011.14+2011+2010.2011}{2011.2025}\)

\(\Rightarrow A=\frac{2011.\left(14+1+2011\right)}{2011.2025}\)

\(\Rightarrow A=\frac{2011.25}{2011.25}\)

\(\Rightarrow A=1\) ( tử số = mẫu số ) 

Vậy \(A=1\)

~ Ủng hộ nhé 

Answer 2

_Vào phần câu hỏi tương tự là có nhé bạn 

Answer 3

\(A=\frac{2012\times14+1997+2010\times2011}{2011\times5+2011\times1008+1012\times2011}\)

\(A=\frac{\left(2011+1\right)\times14+1997+2010\times2011}{2011\times\left(5+1008+1012\right)}\)

\(A=\frac{2011\times14+\left(14+1997\right)+2010\times2011}{2011\times2025}\)

\(A=\frac{2011\times14+2011+2010\times2011}{2011\times2025}\)

\(A=\frac{2011\times\left(14+1+2010\right)}{2011\times2025}\)

\(A=\frac{2011\times2025}{2011\times2025}\)

\(A=1\)