Question

 Tính nhanh A = (1^100+2^100+…+10^100).(5^10-25^5)

B = (2^5+3^5+4^5).(1^2+2^2+…+100^2).(4^10-2^20)

Answer 1

Bạn tự hỏi rồi từ trả lời ! Bạn xem đầu bạn có nóng không ?

Answer 2

olm ko cho tự hỏi tự trả lời đâu nhoa.

Answer 3

`Answer:`

\(A=\left(1^{100}+2^{100}+...+10^{100}\right)\left(5^{10}-25^5\right)\)

\(=\left(1^{100}+2^{100}+...+10^{100}\right)[5^{10}-\left(5^2\right)^5]\)

\(=\left(1^{100}+2^{100}+...+10^{100}\right)\left(5^{10}-5^{10}\right)\)

\(=\left(1^{100}+2^{100}+...+10^{100}\right).0\)

\(=0\)

\(B=\left(2^5+3^5+4^5\right)\left(1^2+2^2+...+100^2\right)\left(4^{10}-2^{20}\right)\)

\(=\left(2^5+3^5+4^5\right)\left(1^2+2^2+...+100^2\right)\left(2^{2.10}-2^{20}\right)\)

\(=\left(2^5+3^5+4^5\right)\left(1^2+2^2+...+100^2\right).0\)

\(=0\)