Killua Zoldyck sai nhé xem tui làm nà
\(=\frac{\left(88985+1\right)\times2003+-678}{88985\times2003+1325}\)
\(=\frac{88985\times2003+2003-678}{88985\times2003+1325}\)
\(=\frac{88985\times2003+1325}{88985\times2003+1325}\)
\(=1\)
Bài giải:
\(\frac{88986\times2003-678}{88985\times2003+1325}=\frac{88986-678}{88985+1325}\)
\(=\frac{88308}{90310}\)
Đáp số: 88308/90310
\(\frac{\left(88985+1\right)\cdot2003-678}{88985\cdot2003+1325}=\frac{88985\cdot2003+2003-678}{88985\cdot2003+1325}=\frac{88985\cdot2003+1325}{88985\cdot2003+1325}=1\)
\(\frac{88986\times2003-678}{88985\times2003+1325}=\frac{\left(88985+1\right)\times2003-678}{88985\times2003+1325}\)
\(=\frac{88985\times2003+2003-678}{88985\times2003+1325}\)
\(=\frac{2003-678}{1325}\)
\(=1\)