\(\left[\left(\frac{40}{130}-\frac{12}{13}\right)\times40\%+0,15\right]:\frac{-5}{52}\)
\(=\left[\left(\frac{4}{13}-\frac{12}{13}\right)\times\frac{40}{100}+\frac{15}{100}\right]:\frac{-5}{52}\)
\(=\left[\frac{-8}{13}\times\frac{2}{5}+\frac{3}{20}\right]\times\frac{-52}{5}\)
\(=\left[-\frac{16}{65}+\frac{3}{20}\right]\times\frac{-52}{5}=-\frac{5}{52}\times\left(-\frac{52}{5}\right)=1\)