a)\(\frac{3}{5}.\frac{7}{9}-\frac{3}{5}.\frac{2}{9}=\frac{3}{5}\left(\frac{7}{9}-\frac{2}{9}\right)=\frac{3}{5}.\frac{5}{9}=\frac{1}{3}\)
b)\(\frac{2006}{2005}.\frac{3}{4}-\frac{3}{4}.\frac{1}{2005}=\frac{3}{4}\left(\frac{2006}{2005}-\frac{1}{2005}\right)=\frac{3}{4}.1=\frac{3}{4}\)
k nhé Cô nàng đáng yêu!
3 / 5 * 7 / 9 - 3 / 5 * 2 / 9 = 15 / 45
2006 / 2005 * 3 / 4 - 3/4 * 1/ 2005 = 1203 / 1604
=\(\frac{3}{5}\)x [\(\frac{7}{9}\)-\(\frac{2}{9}\)]=\(\frac{3}{5}\)x \(\frac{5}{9}\)
=\(\frac{3}{9}\)=\(\frac{1}{3}\)
=\(\frac{3}{4}\)-[\(\frac{2006}{2005}\)-\(\frac{1}{2005}\)]=\(\frac{3}{4}\)x 1=\(\frac{3}{4}\)
\(=\frac{3}{5}\cdot\left(\frac{7}{9}-\frac{2}{9}\right)=\frac{3}{5}\cdot\frac{5}{9}=\frac{1}{3}\)
\(\frac{3}{4}\cdot\left(\frac{2006}{2005}-\frac{1}{2005}\right)=\frac{3}{4}\cdot1=\frac{3}{4}\)
