Question

 tính nhanh 

(2+4+6+...+100).(36.333-108.111)

19991999.1998-19981998.1999

Answer 1

\(Ta\)\(có:\)

\(\text{36.333-108.111}=0\)

\(=>tích\)\(đó=0\)

Answer 2

(2+4+6+...+100).(36.333-108.111

=(2+4+6+...+1000).(36.3.111-108.111)

=(2+4+6+...+1000.(108.111-108.111)

=(2+4+6+...+100).0

0

Answer 3

(2+4+6+..+100).(36.333-108.111)

=(2+4+6+..+100).0

=0

Answer 4

(2 + 4 + 6 + ... + 100).(36.333 - 108.111)

=        A                   .      0 = 0

Answer 5

=0 nhé bạn

Answer 6

(2+4+6+...+100).(36.333-108.111) =(2+4+6...+1000).(36.3.111-108.111) =(2+4+6+...+1000).(108.111-108.111) =(2+4+6+...+1000).0 =0

Answer 7

(2+4+6+...+100).(36.333-108.111
=(2+4+6+...+1000).(36.3.111-108.111)
=(2+4+6+...+1000.(108.111-108.111)
=(2+4+6+...+100).0
0

tk nhé

:3

Answer 8

= 0 nha Phụng. Gần giống tên của mik, là Phượng rồi.

Mọi người ủng hộ mik đi

mik k lại cho.

cảm ơn.