2/1x2 + 2/2x3 +...+ 2/9x10
=2x(1-1/2+1/2-1/3+...+1/9-1/10)
=2x(1-1/10)
=2 x 9/10
=9/5
Đặt A=\(\frac{2}{1.2}+\frac{2}{2.3}+\frac{2}{3.4}+...+\frac{2}{9.10}\)
\(\frac{A}{2}\)=\(\frac{1}{1.2}+\frac{1}{2.3}+\frac{1}{3.4}+...+\frac{1}{9.10}\)
\(\frac{A}{2}\)=\(1-\frac{1}{2}+\frac{1}{2}-\frac{1}{3}+\frac{1}{3}-\frac{1}{4}+...+\frac{1}{9}-\frac{1}{10}\)
\(\frac{A}{2}\)=\(1-\frac{1}{10}\)
\(\frac{A}{2}\)=\(\frac{99}{10}\)
A=\(\frac{9}{20}\)
Vậy A=\(\frac{9}{20}\)