( 1 + 2 + 3 + 4 + ... + 2017 ) . ( 13 . 33 - 39 . 11 )
= ( 1 + 2 + 3 + 4 + ... + 2017 ) . ( 429 - 429 )
= ( 1 + 2 + 3 + 4 + ... + 2017 ) . 0
= 0
k mk nha
=(1+2+3+4+.....+2017).[(13.3)x11-39.11)]
=(1+2+3+.........+2017).[39x(11-11)]
=(1+2+3+......+2017).[39x0]
=(1+2+3+......+2017)x0
=0
2 bạn ơi trả lời cho mình câu trên với
(1+2+3+...+2017)x(13x33—39x11)
=(1+2+3+...+2017)x(39x11—39x11)
=(1+2+3+....+2017)x0
=0
\(\left(1+2+3+4+...+2017\right).\left(13.33-39.11\right)\)
\(=\left(1+2+3+4+...+2017\right).\left(429-429\right)\)
\(=\left(1+2+3+4+...+2017\right).0\)
\(=0\)
