\(2^{n+3}=290-34=256\)
\(\sqrt{256}=16\)
\(\Rightarrow n+3=16\)
\(n=16-3=13\)
2n+3 + 34 = 290
=> 2 n+3 =290-34
=>2n+3 = 256
=>2n+3 = 256 =28
=>n+3=8
=>n=8-3=5
\(2^{n+3}=290-34\)
\(2^{n+3}=256\)
\(2^{n+3}=2^8\)
n +3 =8
n = 5
\(2^{n+3}\)+34=290
\(2^{n+3}\)=290-34
\(2^{n+3}\)=256
\(2^{n+3}\)=\(2^{128}\)
n+3=128
n=128-3=125
vậy n=125 nha bn
2n+3+34 = 290
=> 2n+3 = 290 - 34 = 256
=> 2n = 236 : 23 = 32 = 25
=> n = 5
Ai tíc mình tíc lại nhé!
