Đặt A=\(\left(2^{2009}+2^{2008}+...+2^1+2^0\right)\)
=> 2A=\(2^{2010}+2^{2009}+2^{2008}+...+2^2+2\)
=>2A-A=\(\left(2^{2010}+2^{2009}+2^{2008}+...+2^2+2\right)-\left(2^{2009}+2^{2008}+...+2^1+2^0\right)\)
=> A=22010-20
=>M=22010-A=22010-22010+20=1
đúng nhé!
tính nhanh \(m=2^{2010}-\left(2^{2009}+2^{2008}+...+2^1+2^0\right)\)
1/TÍNH NHANH
a/ \(\frac{\left(2^3.5.7\right).\left(5^2.7^3\right)}{\left(2.5.7^2\right)^2}\)
2/so sánh
a/\(\frac{2009}{2010}va\frac{2010}{2011}\) b/\(\frac{1}{3^{400}}va\frac{1}{4^{300}}\) c/\(\frac{200}{201}+\frac{201}{202}va\frac{200+201}{201+202}\) d/\(\frac{2008}{2008+2009}va\frac{2009}{2009+2010}\)
3/TÌM X BIẾT
\(\left(\frac{2}{1.3}+\frac{2}{3.5}+\frac{2}{5.7}+....+\frac{2}{97.99}\right)-x=\frac{-100}{99}\)
GIÚP MÌNH NHA MAI MÌNH NỘP RÙI
Tìm x, biết:
\(\left(1+\frac{1}{2}+\frac{1}{3}+...+\frac{1}{2008}\right).x=\frac{2009}{1}+\frac{2010}{2}+\frac{2011}{3}+...+\frac{4016}{2008}-2008\)
tính M= 22010 - (22009 + 22008 + ......+ 21 + 20 )
1.Tính tổng
\(S=\left(\frac{-1}{7}\right)^0+\left(\frac{-1}{7}\right)^1+\left(\frac{-1}{7}\right)^2+...+\left(\frac{-1}{7}\right)^{2007}\)
2.Tìm x
\(5^x+5^{x+2}=650\)
3.CMR
\(\frac{1}{6}< \frac{1}{5^2}+\frac{1}{6^2}+\frac{1}{7^2}+...+\frac{1}{100^2}< \frac{1}{4}\)
4. Cho \(A=\frac{1}{2010}+\frac{2}{2009}+\frac{3}{2008}+...+\frac{2009}{2}+\frac{2010}{1}\)
\(B=\frac{1}{2}+\frac{1}{3}+\frac{1}{4}+...+\frac{1}{2010}+\frac{1}{2011}\)
So sánh A và B
Tính:
\(\dfrac{1.2010+2.2009+3.2008+...+2010.1}{\left(1+2+3+...+2010\right)+\left(1+2+3+...+2009\right)+...\left(1+2\right)+1}\)
M=22010-(22009 + 22008 + ... + 21 + 20) = ?
Tìm x thỏa mãn: x + (x + 1) + (x + 2) + … + 2009 + 2010 = 2010 A.-2010 B.-2008 C.0 D.-2009
HELP ME!!!!!!!
tính\(\frac{1\cdot2010+2\cdot2009+3\cdot2008+...+2010\cdot1}{\left(1+2+3+...+2010\right)+\left(1+2+3+...+2009\right)+\left(1+2\right)+1}\):
