=>\(\left(0,125\cdot4\right)^m=243\)
=>\(3^m=243\)
Mà \(3^5=243\)
=>\(m=5\)
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Tính giá trị biểu thức :
a ,\(A=\frac{3^{10}\times11+\left(3^2\right)^5:5}{27\times24}\)
b,\(B=\frac{2^{10}\times13+2^{10}\times65}{28\times104}\)
AI NHANH NHẤT MK K CHO
So sánh:
a)\(\left(\frac{1}{80}\right)^7và\left(\frac{1}{243}\right)^6\)
b)\(\left(\frac{3}{8}\right)^5và\left(\frac{5}{243}\right)^3\)
1, A= \(\dfrac{-3}{4}.\left(0,125-1\dfrac{1}{2}\right):\dfrac{33}{16}-25\%\)
2, B= \(1\dfrac{13}{15}.0,75-\left(\dfrac{11}{20}+25\%\right):\dfrac{7}{3}\)
3, C= \(\dfrac{5}{16}:0,125-\left(2\dfrac{1}{4}-0,6\right).\dfrac{10}{11}\)
4, D= \(6\dfrac{5}{12}:2\dfrac{5}{4}+11\dfrac{1}{4}.\left(\dfrac{1}{3}-\dfrac{1}{5}\right)\)
\(\left(\frac{11}{12}+\frac{11}{12\times13}+\frac{11}{23\times24}+...+\frac{11}{89\times100}\right)+x=\frac{5}{3}\)
Tim x biet
ai guips tui với
so sánh:
a)\(\left(\frac{1}{80}\right)^7và\left(\frac{1}{243}\right)^6\)
b)\(\left(\frac{3}{8}\right)^5và\left(\frac{5}{243}\right)^3\)
giải chi tiết cho mk nha!!!
Rut gon phan so sau :
a)\(\frac{9^{14\times}25^5\times8^7}{18^{12}\times625^3\times24^3}\)
b)\(\frac{1\times3\times5\times...\times39}{21\times22\times23\times...\times40}\)
c)\(\frac{1\times3\times5\times...\times\left(2n-1\right)}{\left(n+1\right)\times\left(n+2\right)\times\left(n+3\right)\times...\times2n}\)
Tính:
\(\frac{\left(0,125\right)}{\left(-0,3\right)^5}^5.\frac{\left(2,4\right)}{\left(0.01\right)^3}^5\)
So sánh:
a) \(12^8\)và \(8^{12}\)
b) \(\left(-5\right)^{39}\)và \(\left(-2\right)^{91}\)
\(So\)\(sanh\):
a)\(\left(\frac{1}{80}\right)^7\)và\(\left(\frac{1}{243}\right)^6\)
b)\(\left(\frac{3}{8}\right)^5\)và \(\left(\frac{5}{243}\right)^3\)
Tìm số tự nhiên x , biết
\(2\cdot\left(x-1\right)^2=8\)
\(\left(2x+1\right)^3=125\)
\(\left(x-2\right)^5=243\)
\(5\left(x-4\right)^2-7=13\)
\(221-\left(3x+2\right)^3=96\)