Question

tính khối lg hỗn hợp gồm 6,72 l khí O2 và 15,68 l H2 ở đktc

Answer 1

\(m_{O_2}=\left(\dfrac{6,72}{22,4}\right).32=9,6g\)

\(m_{H_2}=\left(\dfrac{15,68}{22,4}\right).2=1,4g\)

\(\Rightarrow m_{hh}=9,6+1,4=11g\)

Answer 2

a) \(n_{O_2}=\dfrac{V}{22,4}=\dfrac{6,72}{22,4}=0,3\left(mol\right)\\ m_{O_2}=n.M=0,3.32=9,6\left(g\right)\)

b)\(n_{H_2}=\dfrac{V}{22,4}=\dfrac{15.68}{22,4}=0,7\left(mol\right)\\ m_{H_2}=n.M=0,7.2=1,4\left(g\right)\)