` 42.(x-3)+(x-3).58=-300`
`=>(42+58)(x-3)=-300`
`100(x-3)=-300`
`x-3 = -300/100`
`x-3=-3`
`x = -3+3=0`
Vậy `x=0`
x-3. (42+ 58) =-300
x-3. 100= -300
x-3 = -300: 100
x-3 = -3
x = -3+ 3
x =0
Vậy x= 0.
\(42\cdot\left(x-3\right)+\left(x-3\right)\cdot58=-300\)
\(\Leftrightarrow\left(x-3\right)\left(42+58\right)=-300\)
\(\Leftrightarrow\left(x-3\right)\cdot100=-300\)
\(\Leftrightarrow x-3=-3\)
\(\Leftrightarrow x=0\)