Question

Tính hợp lý   (1-\(\frac{1}{2}\))(1-\(\frac{1}{3}\))(1-\(\frac{1}{4}\))...(1-\(\frac{1}{100}\))

Answer 1

\(\left(1-\frac{1}{2}\right)\left(1-\frac{1}{3}\right)..........\left(1-\frac{1}{100}\right)\)

\(=\frac{1}{2}.\frac{2}{3}............\frac{99}{100}\)

\(=\frac{1.2.3.........99}{2.3...........100}\)

\(=\frac{1}{100}\)

Answer 2

Ta có: \(\left(1-\frac{1}{2}\right)\left(1-\frac{1}{3}\right)...\left(1-\frac{1}{100}\right)\)

=\(\frac{1}{2}.\frac{2}{3}....\frac{99}{100}\)

=\(\frac{1.2....99}{2.3...100}\)

=\(\frac{1}{100}\)

Answer 3

\(\left(1-\frac{1}{2}\right)\left(1-\frac{1}{3}\right)............\left(1-\frac{1}{100}\right)\)

\(=\frac{1}{2}\cdot\frac{2}{3}.........\frac{99}{100}\)

\(=\frac{1.2.3.........99}{2.3............100}\)

\(=\frac{1}{100}\)

# Hok Tốt #