Tình hợp lí
C=(11213.20 +11220.27 +11227.34 +...+11262.69 ):(−59.13 −79.25 −1319.25 −3119.69 )
Tình hợp lí
C=(11213.20 +11220.27 +11227.34 +...+11262.69 ):(−59.13 −79.25 −1319.25 −3119.69 )
\(\frac{\frac{3}{7}-\frac{3}{17}+\frac{3}{37}}{\frac{5}{7}-\frac{5}{17}+\frac{5}{37}}+\frac{\frac{1}{2}-\frac{1}{3}+\frac{1}{4}-\frac{1}{5}}{\frac{7}{5}-\frac{7}{4}+\frac{7}{3}-\frac{7}{2}}\) =?
\(\left(\frac{112}{13.20}+\frac{112}{20.27}+\frac{112}{37.34}+....+\frac{112}{62.69}\right):\left(\frac{5}{9.13}-\frac{7}{19.25}-\frac{13}{19.25}-\frac{31}{19.69}\right)\)=?
Tính hợp lí:
a. A= \(\left(\frac{112}{13.20}+\frac{112}{20.27}+\frac{112}{27.34}+.....+\frac{112}{62.69}\right)\): \(\left(-\frac{5}{9.13}-\frac{7}{9.25}-\frac{13}{19.25}-\frac{31}{19.69}\right)\)
b. B= \(\frac{2.2016}{1+\frac{1}{1+2}+\frac{1}{1+2+3}+\frac{1}{1+2+3+4}+......+\frac{1}{1+2+3+4+.....+2016}}\)
c. C= \(\frac{2^{12}.3^5-4^6.9^2}{\left(2^2.3\right)^6+8^4.3^5}-\frac{5^{10}.7^3-25^5.49^2}{\left(125.7\right)^3+5^9.14^3}\)
Giúp mk vs nha! Mai mk phải nộp rùi
tks m.n nhìu
a.(112/13.20 + 112/ 20.27 + 112/ 27.34 + ... +112/62.69 ) : ( -5/9.13 -7/ 9.25 - 13/19.25 - 31/19.69)
Tính bằng cách hợp lí. Ai giải nhanh mình tick cho
Bài 1:Thực hiện phép tính (hợp lí nếu có)
a,2.8^4.27^2+.6^9/2^7.6^7+27.40.9^4
b,(112/13.20+112/20.27+112/27.34+...+112/62.69):(5/9.13-7/9.25-13/19.25-31/19.69)
c,So sánh : A=1/2^1+1/2^2+...+1/2^49+1/2^50 với 1
\(\frac{-5}{9.13}-\frac{7}{9.25}-\frac{13}{19.25}-\frac{31}{19.69}\)
tính
E=\(\frac{5}{9.13}+\frac{7}{9.25}+\frac{13}{19.25}+\frac{31}{19.39}\)
Tìm số tự nhiên x thỏa mãn
a, \(\frac{112}{34}=\frac{56}{x};\) \(\frac{x-2}{255}=\frac{144}{153}\) c,\(\frac{58}{27}\times\frac{54}{29}< x< \frac{100}{13}-\frac{9}{13}\) b,\(\frac{7}{15}< \frac{x}{40}< \frac{8}{15}\) d,\(\left(1\frac{1}{4}-\frac{3}{5}\right):\frac{17}{20}< \frac{x}{17}< \left(5\frac{1}{3}-3\frac{1}{2}\right)\times\frac{12}{17}\)
Thực hiện phép tính (hợp lí nếu có thể):
\(1,\frac{-1}{3}-\frac{-3}{5}-\frac{1}{6}+\frac{1}{43}-\frac{-3}{7}+\frac{-1}{2}-\frac{1}{35}\\ \\ 2,\left(-\frac{1}{3}+\frac{7}{13}\right)-\left(\frac{-16}{24}+\frac{6}{26}+\frac{9}{13}\right)\)\(3,\frac{-7}{3}-\left[\frac{2}{5}-\left(\frac{1}{3}+\frac{-5}{25}\right)\right]\\ 4,\left(2\frac{1}{4}-3\frac{1}{5}\right)-\left[\frac{-3}{4}+\left(\frac{4}{5}-2019\right)\right]\)
so sánh = cách hợp lí
P1 =\(\left(-\frac{43}{51}\right)\cdot\left(\frac{-19}{80}\right)\)
P2 = \(\left(-\frac{7}{13}\right)\cdot\left(-\frac{4}{65}\right)\cdot\left(-\frac{8}{31}\right)\)
P3= \(-\frac{5}{10}\cdot-\frac{4}{10}\cdot-\frac{3}{10}....\frac{3}{10}\cdot\frac{4}{10}\cdot\frac{5}{10}\)