\(a,-\frac{4}{7}+\left(-\frac{2}{3}+\frac{3}{7}\right)=-\frac{4}{7}-\frac{2}{3}+\frac{3}{7}=-\frac{4}{7}+\frac{3}{7}-\frac{2}{3}=-\frac{1}{7}-\frac{2}{3}=-\frac{17}{21}\)
\(b,-\frac{3}{10}\cdot\frac{5}{12}+-\frac{3}{10}\cdot\frac{7}{12}+5\cdot\frac{3}{10}=\frac{3}{10}\cdot-\frac{5}{12}+\frac{3}{10}\cdot-\frac{7}{12}+5\cdot\frac{3}{10}=\frac{3}{10}\cdot\left(-\frac{5}{12}-\frac{7}{12}+5\right)\)
\(=\frac{3}{10}\cdot4=\frac{6}{5}\)
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a, -4/7 + (-2/3 + 3/7 )
= -4/7 + (-2/3) + 3/7
= -4/7 + 3/7 + (-2/3)
= -1/7 + -14/21
= -3/21 + -14/21
= -17/21
b, -3/10 . 5/12 + -3/10 . 7/12 + 5. - 3/10
-3/10.(5/12 + 7/12 + 60/12)
-3/10.6
-18/10= -9/5