Question

Tính hiệu:

\(\left(2,4x^2+1,7y^2+2xy\right)-\left(0,4x^2-1,3y^2+xy\right)\)

Answer 1

(2,4x² + 1,7y² +2xy) - (0,4x² -1,3y² +xy)
= 2,4x² + 1,7y² +2xy - 0,4x² +1,3y² -xy
= (2,4x² - 0,4x² ) + (1,7y² + 1,3y² ) +(2xy - xy)
=2x² + 3y² +xy

Answer 2

(2,4x² + 1,7y² +2xy) - (0,4x² -1,3y² +xy)

=`2,4x^2+1,7y^2+2xy-0,4x^2+1,3y^2-xy`

`=(2,4x^2-0,4x^2)+(1,7y^2+1,3y^2)+(2xy-xy)`

`=2x^2+3y^2+xy`