\(b=1.1+2.2+...+98.98=1\left(2-1\right)+2\left(3-1\right)+..+98.\left(99-1\right)=\left(1.2+2.3+...+98.99\right)-\left(1+2+...+98\right)\)=> \(a-b=\left(1.2+2.3+..+98.99\right)-\left[\left(1.2+2.3+...+98.99\right)-\left(1+2+...+98\right)\right]=1+2+3+...+98\)ta tính tổng của dãy số: a-b= (98+1).98:2=4851
A = 1x2 + 2x3 + 3x4 + 4x5 + ...+ 99x100
A x 3 = 1x2x3 + 2x3x3 + 3x4x3 + 4x5x3 + ... + 99x100x3
A x 3 = 1x2x3 + 2x3x(4-1) + 3x4x(5-2) + 4x5x(6-3) + ... + 99x100x(101-98)
A x 3 = 1x2x3 + 2x3x4 - 1x2x3 + 3x4x5 - 2x3x4 + 4x5x6 - 3x4x5 + ... + 99x100x101 - 98x99x100.
A x 3 = 99x100x101
A = 99x100x101 : 3
A = 333300
B = ... (bạn tự tính)
=> A - B = ...