Coi như pt đã cho có 2 nghiệm, khi đó: \(\left\{{}\begin{matrix}x_1+x_2=\dfrac{-2m^2+2}{m^2+1}=-2+\dfrac{4}{m^2+1}\\x_1x_2=\dfrac{m}{m^2+1}\end{matrix}\right.\)
\(\Rightarrow\left\{{}\begin{matrix}x_1+x_2+2=\dfrac{4}{m^2+1}\\x_1x_2=\dfrac{m}{m^2+1}\end{matrix}\right.\)
\(\Rightarrow\left\{{}\begin{matrix}m^2+1=\dfrac{4}{x_1+x_2+2}\\x_1x_2=\dfrac{m}{m^2+1}=\dfrac{m}{4}\left(x_1+x_2+2\right)\end{matrix}\right.\)
\(\Rightarrow\left\{{}\begin{matrix}m^2=\dfrac{2-x_1-x_2}{x_1+x_2+2}\\x_1x_2=\dfrac{m}{4}\left(x_1+x_2+2\right)\end{matrix}\right.\)
\(\Rightarrow x_1x_2=\pm\dfrac{1}{4}\left(x_1+x_2+2\right)\sqrt{\dfrac{2-x_1-x_2}{x_1+x_2+2}}\)
