Question

Tính giá trị của các biểu thức sau:

A = \(8\frac{2}{7}-\left(3\frac{4}{9}+4\frac{2}{7}\right)\)

B = \(\left(10\frac{2}{9}+2\frac{3}{5}\right)-6\frac{2}{9}\)

Answer 1

Ta có : \(A=8\frac{2}{7}-\left(3\frac{4}{9}+4\frac{2}{7}\right)\)

\(\Rightarrow A=\frac{58}{7}-\left(\frac{31}{9}+\frac{30}{7}\right)\)

\(\Rightarrow A=\frac{58}{7}-\frac{487}{63}=\frac{5}{9}\)

P/s:Câu B tương tự nhé

Answer 2

Tiếp B của @Phạm Tuấn Đạt

\(B=\left(10\frac{2}{9}+2\frac{3}{5}\right)-6\frac{2}{9}\)

\(\Rightarrow B=\left(\frac{92}{9}+\frac{13}{5}\right)-\frac{56}{9}\)

\(B=\left(\frac{92}{9}-\frac{56}{9}\right)+\frac{13}{5}\)

\(B=\frac{36}{9}+\frac{13}{5}\)

\(B=4+\frac{13}{5}\)

\(B=\frac{20}{5}+\frac{13}{5}=\frac{33}{5}\)

Answer 3

a=58/7-(31/9+30/7)

a=58/7-(217/63+270/63)

a=58/7-487/63

a=5222/63-487/63

a=35/63

Answer 4

b=(92/9+13/5)-56/9

b=(460/45+117/45)-56/9

b=577/45-280/45

b=297/45