\(C=1.99+2.98+3.97+...+98.2+99.1\)
\(=1.99+2.\left(99-1\right)+3.\left(99-2\right)+...+98.\left(99-97\right)+99.\left(99-98\right)\)
\(=1.99+2.99+3.99+...+98.99+99.99-\left(1.2+2.3+...+97.98+98.99\right)\)
\(A=1.99+2.99+...+99.99\)
\(B=1.2+2.3+...+98.99\)
\(A=1.99+2.99+...+99.99\)
\(=99.\left(1+2+...+99\right)\)
\(=99.\frac{99.\left(99+1\right)}{2}=490050\)
\(B=1.2+2.3+...+98.99\)
\(3B=1.2.3+2.3.\left(4-1\right)+...+98.99.\left(100-97\right)\)
\(=1.2.3+2.3.4-1.2.3+...+98.99.100-97.98.99\)
\(=98.99.100\)
\(B=\frac{98.99.100}{3}=323400\)
\(C=A-B=166650\)
