Question

tính giá trị của biểu thức

Answer 1

\(1,=\dfrac{16\cdot16+16\cdot1-5}{16\cdot16+11}=\dfrac{16\cdot16+11}{16\cdot16+11}=1\)

\(3,=\dfrac{\left(65+135\right)+\left(891+909\right)}{\left(731+69\right)-\left(47+253\right)}=\dfrac{200+1800}{800-300}=\dfrac{2000}{500}=4\)

 

 

 

 

 

 

 

 

Answer 2

\(1,\dfrac{16.17-5}{16.16+11}=\dfrac{272-5}{256+11}=\dfrac{267}{267}=1\)

 

\(3,\dfrac{65+891+135+909}{731-47+69-253}=\dfrac{2000}{500}=4\)

Answer 3

`a, = (16 xx 16 + 16 - 5)/(16 xx 16 + 11)`

`= (16 xx 16+11)/(16xx16+11)`

`=1`

`b, = ((65+135) + (891+909))/((731+69) - (253 - 47))`

`= 2000/500 = 4`