Tính giá trị các biểu thức sau theo cách hợp lí nhất.
a) $\mathrm{A}=\left(\dfrac{2}{7} \cdot \dfrac{1}{4}-\dfrac{1}{3} \cdot \dfrac{2}{7}\right):\left(\dfrac{2}{7} \cdot \dfrac{3}{9}-\dfrac{2}{7} \cdot \dfrac{2}{5}\right)$;
b) $\mathrm{B}=\dfrac{\left(\dfrac{1}{5}-\dfrac{2}{7}\right) \cdot \dfrac{3}{4}-\dfrac{3}{4} \cdot\left(\dfrac{1}{3}-\dfrac{2}{7}\right)}{\dfrac{1}{5} \cdot \dfrac{2}{7}-\dfrac{1}{3} \cdot\left(\dfrac{2}{7}+\dfrac{3}{9}\right)+\dfrac{3}{9} \cdot \dfrac{1}{5}} .$
\(a,A=\left(\dfrac{2}{7}.\dfrac{1}{4}-\dfrac{1}{3}.\dfrac{2}{7}\right):\left(\dfrac{2}{7}.\dfrac{3}{9}-\dfrac{2}{7}.\dfrac{2}{5}\right)\)
\(A=\left[\dfrac{2}{7}\left(\dfrac{1}{4}-\dfrac{1}{3}\right)\right]:\left[\dfrac{2}{7}.\left(\dfrac{1}{3}-\dfrac{2}{5}\right)\right]\)
\(A=\left(\dfrac{2}{7}.\dfrac{-1}{12}\right):\left(\dfrac{5}{15}-\dfrac{6}{15}\right)\)
\(A=\dfrac{-1}{42}:\dfrac{-1}{15}\)
\(A=\dfrac{-1}{42}.\dfrac{15}{-1}\)
\(A=\dfrac{5}{14}\)
\(a,A=\left(\dfrac{2}{7}.\dfrac{1}{4}-\dfrac{1}{3}.\dfrac{2}{7}\right):\left(\dfrac{2}{7}.\dfrac{3}{9}-\dfrac{2}{7}.\dfrac{2}{5}\right)\)
\(A=\left[\dfrac{2}{7}\left(\dfrac{1}{4}-\dfrac{1}{3}\right)\right]:\left[\dfrac{2}{7}.\left(\dfrac{1}{3}-\dfrac{2}{5}\right)\right]\)
\(A=\left(\dfrac{2}{7}.\dfrac{-1}{12}\right):\left(\dfrac{5}{15}-\dfrac{6}{15}\right)\)
\(A=\dfrac{-1}{42}:\dfrac{-1}{15}\)
\(A=\dfrac{-1}{42}.\dfrac{15}{-1}\)
\(A=\dfrac{5}{14}\)
a) A = (\(\dfrac{2}{7}.\dfrac{1}{4}-\dfrac{1}{3}.\dfrac{2}{7}\) ) : ( \(\dfrac{2}{7}.\dfrac{3}{9}-\dfrac{2}{7}.\dfrac{2}{5}\) ) = \(\left[\dfrac{2}{7}\left(\dfrac{1}{4}-\dfrac{1}{3}\right)\right]:\left[\dfrac{2}{7}\left(\dfrac{1}{3}-\dfrac{2}{5}\right)\right]\)
= \(1\dfrac{1}{4}\)
\(a,A=(\dfrac{2}{7}.\dfrac{1}{4}-\dfrac{1}{3}.\dfrac{2}{7}):(\dfrac{2}{7}.\dfrac{3}{9}-\dfrac{2}{7}.\dfrac{2}{5})\)
\(=(\dfrac{1}{4}-\dfrac{1}{3}):(\dfrac{1}{3}-\dfrac{2}{5})\)
\(=1\dfrac{1}{4}\)
\(b,B=\dfrac{\dfrac{3}{4}(\dfrac{1}{5}-\dfrac{2}{7}-\dfrac{1}{3}+\dfrac{2}{7})}{\dfrac{1}{5}(\dfrac{2}{7}+\dfrac{1}{3})-\dfrac{1}{3}(\dfrac{2}{7}+\dfrac{1}{3})}\)
\(=\dfrac{\dfrac{3}{4}(\dfrac{1}{5}-\dfrac{1}{3})}{(\dfrac{1}{5}-\dfrac{1}{3})(\dfrac{2}{7}+\dfrac{1}{3})}\)
\(=1\dfrac{11}{52}\)
A = ( 2/7 . 1/4 - 1/3 . 2/7 ) : ( 2/7 . 3/9 - 2/7 . 2/5 )
A = 2/7 . [( 1/4 - 1/3 ) : ( 3/9 - 2/5 )]
A = 2/7 . [ -1/12 : -1/15 ]
A = 2/7 . 5/4
A = 5/14
B = ( 1/5 - 2/7 ) . 3/4 - 3/4 . ( 1/3 - 2/7 ) / 1/5 . 2/7 - 1/3 . ( 2/7 + 3/9 ) + 3/9 . 1/5
B = 3/4 - 3/4 / 3/9 + 3/9
B = 0 : 2/3
B = 0
a,A=[2/7(1/4-1/3)]:[2/7(1/3-2/5)]
=(1/4-1/3):(1/3-2/5)
=6/4
b, B= .3/4(1/5-2/7-1/3+2/7)/1/5(2/7+1/3)-1/3(2/7+1/3)
=3/4(1/5-1/3)/(1/5-1/3)(2/7+1/3)
=63/52
A=(2/7.1/4-1/3.2/7):(2/7.3/9-2/7.2/5)
=2/7.(1/4-1/3):(2/7.(3/9-2/8))
=2/12-4/12):(15/45-18/45)
=-1/12.45/-3=5/4
B=(1/5-2/7).3/4-3/4.(1/3-2/7)
_______________________
1/5.2/7-2/7-1/3+2/7+3/9)=3/4.1/5
=3/4.(1/5-2/7-1/3+2/7)
_________________
1/5-(2/7+3/9)-1/3918/63=21/63)
=3/4.(1/5-1/3)
__________________________
1/5-(18/63+21/63)-1/3(19/63+21/63)
=3/4.(1/5-1/3)
_____________________________
(1/5-1/3)18/63+21/63)
=3/4:39/63=3/4.21/13=63/52
a) A = \(\dfrac{5}{4}\)
b) B =\(\dfrac{63}{52}\)
a) A= \(\dfrac{2}{7}\times(\dfrac{1}{4}-\dfrac{1}{3})\div\dfrac{2}{7}\times(\dfrac{3}{9}-\dfrac{2}{5})\)
A= \(\dfrac{2}{7}\times\dfrac{7}{12}\div\dfrac{2}{7}\times\dfrac{-1}{15}\)
A= \(\dfrac{1}{6}\div\dfrac{-2}{105}\)
A= \(\dfrac{-35}{4}\)
b) B= \(\dfrac{(\dfrac{1}{5}-\dfrac{2}{7})\times\dfrac{3}{4}-\dfrac{3}{4}(\dfrac{1}{3}-\dfrac{2}{7})}{\dfrac{1}{5}\times\dfrac{2}{7}-\dfrac{1}{3}(\dfrac{2}{7}+\dfrac{3}{9})+\dfrac{3}{9}\times\dfrac{1}{5}}\)
B=\(\dfrac{\dfrac{3}{4}(\dfrac{1}{5}-\dfrac{2}{7}-\dfrac{1}{3}+\dfrac{2}{7})}{\dfrac{1}{5}\times\dfrac{2}{7}-\dfrac{1}{3}\times\dfrac{2}{7}+\dfrac{1}{3}\times\dfrac{3}{9}+\dfrac{3}{9}\times\dfrac{1}{5}}\)
B= \(\dfrac{\dfrac{3}{4}[(\dfrac{1}{5}-\dfrac{1}{3})-(\dfrac{2}{7}-\dfrac{2}{7})]}{\dfrac{2}{7}(\dfrac{1}{5}-\dfrac{1}{3})+\dfrac{3}{9}(\dfrac{1}{3}-\dfrac{1}{5})}\)
B=\(\dfrac{\dfrac{3}{4}(-\dfrac{2}{15}+\dfrac{1}{7})}{\dfrac{2}{7}\times(\dfrac{-2}{15})+\dfrac{3}{9}\times(\dfrac{2}{5})}\)
B= \(\dfrac{\dfrac{3}{4}\times(\dfrac{-2}{15})}{\dfrac{2}{7}(-\dfrac{2}{15})+\dfrac{3}{9}\times\dfrac{2}{15}}\)
B=\(\dfrac{\dfrac{3}{4}\times(\dfrac{-2}{15})}{\dfrac{2}{7}(\dfrac{-2}{15})+\dfrac{1}{3}\times\dfrac{2}{15}}\)
B=\(\dfrac{\dfrac{3}{4}}{(\dfrac{2}{7}-\dfrac{1}{3})}\)
B=\(\dfrac{\dfrac{3}{4}}{\dfrac{-1}{21}}\)
B=\(\dfrac{3}{4}\times(\dfrac{-21}{1})\)
B=\(\dfrac{63}{4}\)