Question

Tính giá trị biểu thức(tính hợp lý nếu có thể)

a)A = \(\frac{4x0,125x20,2x800x0,25}{1,01x75+0,26x101-1,01}\)

b)B =  (\(\frac{178}{179}\)+\(\frac{179}{180}\)+\(\frac{180}{181}\))   x   (\(\frac{80}{56}\)-\(\frac{15}{12}\):\(\frac{7}{8}\))

Answer 1

\(A=\frac{4\cdot0,125\cdot20,2\cdot800\cdot0,25}{1,01\cdot75+0,26\cdot101-1,01}\)   

\(=\frac{4\cdot0,25\cdot0,125\cdot800\cdot20,2}{1,01\cdot75+0,26\cdot100\cdot1,01-1,01}\)   

\(=\frac{1\cdot100\cdot20,2}{1,01\cdot\left(75+26-1\right)}\)   

\(=\frac{100\cdot20,2}{100\cdot1,01}\)   

= 20 

\(B=\left(\frac{178}{179}+\frac{179}{180}+\frac{180}{181}\right)\cdot\left(\frac{80}{56}-\frac{15}{12}:\frac{7}{8}\right)\)   

\(=\left(\frac{178}{179}+\frac{179}{180}+\frac{180}{181}\right)\cdot\left(\frac{10}{7}-\frac{5}{4}\cdot\frac{8}{7}\right)\)   

\(=\left(\frac{178}{179}+\frac{179}{180}+\frac{180}{181}\right)\cdot\left(\frac{10}{7}-\frac{10}{7}\right)\)   

\(=\left(\frac{178}{179}+\frac{179}{180}+\frac{180}{181}\right)\cdot0\)   

= 0