\(=8\frac{4}{17}-2\frac{5}{9}+3\frac{4}{17}=\left(8+3\right)\frac{4}{17}-2\frac{5}{9}=11\frac{4}{17}-2\frac{5}{9}\)
Chỉ cần k!
Nếu muốn giải đc..
Phải k cho mk,mk sẽ giải cho!
\(A=8\frac{4}{17}-\left(2\frac{5}{9}+3\frac{4}{17}\right)\)
\(A=8+\frac{4}{17}-\left(2+\frac{5}{9}+3+\frac{4}{17}\right)\)
\(A=8+\frac{4}{17}-2-\frac{5}{9}-3-\frac{4}{17}\)
\(A=\left(8-2-3\right)+\left(\frac{4}{17}-\frac{4}{17}\right)-\frac{5}{9}\)
\(A=3-\frac{5}{9}\)
\(A=\frac{27-5}{9}=\frac{22}{9}\)
\(A=8\frac{4}{17}-\left(2\frac{5}{9}+3\frac{4}{17}\right)\)
\(=8\frac{4}{17}-2\frac{5}{9}-3\frac{4}{17}\)
\(=\left(8\frac{4}{17}-3\frac{4}{17}\right)-2\frac{5}{9}\)
\(=5-\frac{23}{9}=\frac{22}{9}\)
Vậy \(A=\frac{22}{9}\)
