Question

Tính giá trị biểu thức sau:

A=(1/2+1).(1/3+1).(1/4+1)........(1/99+1)

Answer 1

\(A=\left(\frac{1}{2}+1\right)\left(\frac{1}{3}+1\right)........\left(\frac{1}{99}+1\right)\)

\(A=\frac{3}{2}.\frac{4}{3}.............\frac{100}{99}=\frac{3.4....................100}{2.3.................99}=\frac{\left(3.4.......99\right).100}{2.\left(3.4...........99\right)}=\frac{100}{2}=50\)

Vậy A=50

Answer 2

A=\(\left(\frac{1}{2}+1\right).\left(\frac{1}{3}+1\right)..............\left(\frac{1}{99}+1\right)\)

=\(\frac{3}{2}.\frac{4}{3}.............\frac{100}{99}\)

=\(\frac{100}{2}\)=50

Answer 3

=50 nha bn

Answer 4

\(\Rightarrow A=\frac{3}{2}.\frac{4}{3}.\frac{5}{4}.......\frac{100}{99}\)

\(\Rightarrow A=\frac{3.4.5.6........100}{2.3.4.........99}\)

\(\Rightarrow A=\frac{100}{2}=50\)

Answer 5

A = 3/2.4/3.5/4...100/99

A = 3.4.5.6....100/2.3.4.5....99

A = 100/2 

A = 50

Answer 6

Đáp số: 50

Ai thấy đúng thì k nha

Answer 7

\(A=\frac{3}{2}.\frac{4}{3}....\frac{100}{99}\)

\(A=\frac{3.4....100}{2.3...99}\)

\(A=\frac{100}{2}=50\)