Question

tinh gia tri bieu thuc  sau 

\(x^3-3x^2+3x-1\) tai x=101

\(x^3+9x^2+27x+27\)tai x=97

Answer 1

x³-3x²+3x-1=x³-3x².1+3x.1²-1³

=(x-1)³

thay x=101 ta được:

(101-1)³=100³=1000000

x³+9x²+27x+27=x³+3x².3+3.x.3²+3³

=(x+3)³

thay x=97 ta được:

(97+3)³=100³=1000000

Answer 2

x^3-3x^2+3x-1

x^3+9x^2+27x+27

=x^3+3*x^2*3+3*x*3^2+3^3

=(x+3)^3

thayx=97 ta duoc :(97+3)^3=100^3=1000000