\(\text{a)Với x = -23 để A = }3(-23)+5(-23)-15(-23)+12(-23-1)\)
\(\text{Ta có : }A=3+5-15(-23)+12(-23-1)\)
\(A=-7\cdot(-23)+12\cdot(-24)\)
\(A=161+(-288)=-127\)
Còn bài b tương tự
\(A=3x+5x-15x+12\left(x-1\right)\)
\(A=x\left(3+5-15\right)+12\left(x-1\right)\)
\(A=-23\cdot-7+12\cdot-24\)
\(A=-127\)
\(3\left(2x+1\right)+7\left(x-5\right)-100x\)
\(=3\cdot31+7\cdot10-15000\)
\(=-14837\)