\(n=\left(1+\sqrt{3}+\sqrt{5}\right)\left(1+\sqrt{3}-\sqrt{5}\right)\)
\(n=\left(1+\sqrt{3}\right)^2-\sqrt{5}^2\)
\(n=1+2.\sqrt{3}.1+3-25\)
\(n=4-25+2\sqrt{3}\)
\(n=-21+2\sqrt{3}\)
tinh Gia tri cua bieu thuc A=a^4-4a^3+a^2+6a+4/(a^2-2a+12) tai a= can cua 5 +1
gia tri lon nhat cua bieu thuc P=can bac hai cua (3+2x-x^2)
gia tri nho nhat cua bieu thuc : (x^2+2)/(can x^2+1)
BAI 1 TINH GIA TRI CUA BTHUC
A=3PHAN 1+CAN 3 -2PHAN 1-CAN 3
B=CAN 10-CAN 5 PHAN CAN 2-1 -3CAN 5 +5PHAN CAN 5+3 +2 PHAN CAN 2
BAI 2 GIAI PT
a)CAN 49-28X+4X MU 2 -5=0
b)1PHAN 2 CAN X-2 -4 CAN 4X -8 PHAN 9 +CAN 9X+18 -5=0
MOI NGUOI GIUP MINH VS MINH CAN LUON BAY GIO
CAM ON
don gian cac bieu thuc
can (2 + can 3) - can(2 - can 3)
Tim Gia Tri Nho Nhat Cua
a) A = x - 4 can x + 9
b) B = x - 3 can x - 10
c ) C = x - can x + 1
d ) D = x + can x + 2
Tinh gia tri bieu thuc:
S=13-33+53-73+...+20153
tinh C=can(1+1/2^2 +1/3^2)+ can(1+1/3^2 +1/4^2)+can(1+1/4^2 + 1/5^2)+...+can(1+1/2002^2 +1/2003^2)
\(2\sqrt{3+\sqrt{5-\sqrt{13+\sqrt{48}}}}\)
tinh gia tri bieu thuc
