Question

tinh gia tri bieu thuc : A=3+3^2+3^3+3^4....3^100

 hay giup minh cau nay kho qua !

Answer 1

^ la gi ha ban

Answer 2

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Answer 3

=>3A=3^2+3^3+3^4+3^5+.....+3^101

=>3A-A=3^101-3

=>2A=3^101-3

=>A=3^101-3/2

vậy A=3^101-3/2

Answer 4

3A=3²+3³+3⁴+3⁵+...........+3¹⁰¹

=>3A-A=3¹⁰¹-3

=>2A=3¹⁰¹-3

=>A=\(\frac{3^{101}-3}{2}\)

Answer 5

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Answer 6

3A=3^2+3^3+3^4+....+3^100+3^101

3A-A=(3^2+3^3+3^4+....+3^100+3^101)-(3+3^2+3^3+3^4+...+3^100)

2A=3^101-3

A=(3^101/2)-(3/2)

Answer 7

=> 3A = 3. ( 3 + 3² + 3³ + 3⁴ + .... + 3¹⁰⁰ )

=> 3A = 3² + 3³ + 3⁴ + 3⁵ + .... + 3¹⁰¹

=> 3A - A = ( 3² + 3³ + 3⁴ + 3⁵ + .... + 3¹⁰¹ ) - ( 3 + 3² + 3³ + 3⁴ + .... + 3¹⁰⁰ )

=> 2A = 3¹⁰¹ - 3

=> A = \(\frac{3^{101}-3}{2}\)

Answer 8

 A=3+3²+3³+3⁴+...+3¹⁰⁰

3A=3²+3³+3⁴+3^5+...+3¹⁰¹

3A-A=3¹⁰¹-3

2A=3¹⁰¹-3

A=(3¹⁰¹-3) : 3

Answer 9

3A= 3^2 + 3^2 + 3^3 + 3^4 +...........+ 3^101

3A-A=(3^2 + 3^2 + 3^3 + 3^4 +.......+ 3^101) - ( 3 + 3^2 + 3^3+ 3^4+................+3^100)

2A=3^2 +3^101-3

2A=3^103 - 3

A= \(\frac{3^{103}-3}{2}\)

Answer 10

102 - 1 = 101