Các câu hỏi tương tự
tinh gia tri bieu thuc a = \(\sqrt{4+\sqrt[3]{8+\frac{2}{3}+3^{10}}\frac{1}{1\times2}+\frac{1}{2\times3}+...+\frac{1}{99\times100}}\)
tinh gia tri bieu thuc a = \(\sqrt{4+\sqrt[3]{8}+\frac{2}{3}+3^{10}}\frac{1}{1\times2}+\frac{1}{2\times3}+...+\frac{1}{99\times100}\)
tinh gia bieu thuc a = \(\sqrt{4+\sqrt[3]{8}}+\frac{2}{3}+3^{10}+\frac{1}{1\times2}+\frac{1}{2\times3}+...+\frac{1}{99\times100}\)
Chứng minh rằng: \(\frac{1\times2-1}{2!}+\frac{2\times3-1}{3!}+\frac{3\times4-1}{4!}+...+\frac{99\times100-1}{100!}<2\)
1) Tinh gia tri cua bieu thuc:
A=\(\frac{\left(1+2+...+100\right)\left(\frac{1}{2}-\frac{1}{3}-\frac{1}{4}-\frac{1}{5}\right)\left(2,4.42-21.4,8\right)}{1+\frac{1}{2}+\frac{1}{3}+\frac{1}{4}+...+\frac{1}{100}}\)
B=\(\frac{4^6.9^5+6^9.120}{-8^4.3^{12}+6^{11}}\)
\(A=\left[1-\left(\frac{1}{1\times2\times3}+\frac{1}{2\times3\times4}+......+\frac{1}{98\times99\times100}\right)\right]\times\frac{14851}{19800}\)
Tính \(\frac{1}{1\times2\times3}+\frac{1}{2\times3\times4}+...+\frac{1}{98\times99\times100}\)
goi A la tap hp cac so nguyen duong x sao cho gia tri cua bieu thuc :\(\frac{2\sqrt{x}+3}{\sqrt{x}-1}\) nguyen
Cho bieu thuc A = \(^{x2+4x+3}\)
a Tinh gia tri bieu thuc tai x= \(\frac{-1}{2}\)
b Tinh gia tri x de bieu thuc A bang 0