Question

 tinh gia tri bieu thuc a =\(\frac{1}{1\times2}+\frac{1}{2\times3}+...+\frac{1}{99\times100}\)

Answer 1

\(A=1-\frac{1}{2}+\frac{1}{2}-\frac{1}{3}+...+\frac{1}{99}-\frac{1}{100}\)

\(A=1-\frac{1}{100}\)

\(A=\frac{99}{100}\)

Answer 2

\(A=1-\frac{1}{2}+\frac{1}{2}-\frac{1}{3}+...+\frac{1}{99}-\frac{1}{100}\)

     \(=1-\frac{1}{100}\)

     \(=\frac{99}{100}\)

Answer 3

\(A=1-\frac{1}{2}+\frac{1}{2}-\frac{1}{3}+...+\frac{1}{99}-\frac{1}{100}\)

\(=1-\frac{1}{100}\)

\(=\frac{99}{100}\)

Answer 4

a = 1/1.2 + 1/2.3 +...+1/99.100

a= 1-1/2 +1/2-1/3+...+1/99-1/100

a= 1 - 1/100

a= 99/100

k nha

Answer 5

Kết quả là : \(\frac{99}{100}\)

Tk cho mk nhéHO BINH AN và cả các bn nữa!!!