ta co:A = 11.329-915/ (2.314)2
=11.329-(32)15/22.328
=11.329-330/22.328
=329.(11-3)/22.328
= 3.7/4
=21/4
\(\frac{11.3^{29}-9^{15}}{\left(2.3^{14}\right)^2}=\frac{11.3^{29}-\left(3^2\right)^{15}}{2^2.3^{28}}=\frac{11.3^{29}-3^{30}}{2^2.3^{28}}=\frac{3^{29}\left(11-3\right)}{2^2.3^{28}}=\frac{3^{29}.8}{2^2.2^{28}}=\frac{3^{29}.2^3}{3^{28}.2^2}=\frac{3.2}{1.1}=6\)
Bằng 6 đấy các bạn ạ.Mình chắc chắn luôn.