\(\dfrac{7}{9}\)
\(\dfrac{43}{32}\)
\(\dfrac{1}{3}\)
\(\dfrac{45}{63}+\dfrac{28}{63}-\dfrac{24}{63}=\dfrac{49}{63}=\dfrac{7}{9}\)
\(\dfrac{31}{32}+\dfrac{11}{16}=\dfrac{31}{32}+\dfrac{22}{32}=\dfrac{43}{32}\)
\(\dfrac{5}{6}\times\dfrac{4}{3}-\dfrac{7}{9}=\dfrac{10}{9}-\dfrac{7}{9}=\dfrac{3}{9}=\dfrac{1}{3}\)