AI GIÚP MÌNH ĐIIIII...........!MÌNH CẦN GẤP LẮM
Ta có: \(\frac{\left(\frac{11^2}{200}+0,415\right):0,01}{\frac{1}{12}-37,25+3\frac{1}{6}}=\frac{\left(\frac{121}{200}+\frac{19}{40}\right).100}{\frac{1}{12}-\frac{149}{4}+\frac{17}{6}}\)
\(=\frac{108}{-\frac{103}{3}}=-\frac{324}{103}\)